What is the surface area of the cylinder with height 3 m and radius 6 m? Round your answer to the nearest thousandth.

Answer 1

The formula for the surface area of a cylinder is $2\pi rh + 2\pi r^2$, where $r$ is the radius and $h$ is the height. In this case, $r=6$ m and $h=3$ m, so the surface area is $2\pi(6)(3)+2\pi(6^2)=36\pi+72\pi=108\pi$. Since $\pi$ is approximately 3.14159, it follows that the surface area is approximately $108(3.14159)\approx \boxed{339.292}$.