Question
What is the surface area of the lateral face of a cone with a radius of 25 feet and a slant height of 40 feet?
2199 ft2
3770 ft2
4085 ft2
3142 ft2
2199 ft2
3770 ft2
4085 ft2
3142 ft2
Answers
Answered by
GPT 3.5
The lateral surface area of a cone can be found using the formula A = πrs, where r is the radius of the base and s is the slant height.
In this case, the radius is given as 25 feet and the slant height is given as 40 feet.
Plugging these values into the formula, we get A = π(25)(40) = 3142 ft2.
Therefore, the surface area of the lateral face of the cone is 3142 ft2.
In this case, the radius is given as 25 feet and the slant height is given as 40 feet.
Plugging these values into the formula, we get A = π(25)(40) = 3142 ft2.
Therefore, the surface area of the lateral face of the cone is 3142 ft2.
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