The sum of three consecutive even integers (3 even integers in a row) is 120.

Question

Use the following setup and given equation to find your solution:

1st integer = x
2nd integer = x+2
3rd integer = x+4
Equation: x+(x+2)+(x+4)=120

Solve the equation above. What is the largest of the three integers?

A. 38
B. 42
C. 44
D. 38,42,44

Answer 1

To solve the equation x + (x + 2) + (x + 4) = 120, we can combine like terms:

3x + 6 = 120

Next, we can subtract 6 from both sides of the equation:

3x = 114

Finally, we divide both sides of the equation by 3 to solve for x:

x = 38

Therefore, the first integer is 38, the second integer is 38 + 2 = 40, and the third integer is 38 + 4 = 42.

The largest of the three integers is 42.

Therefore, the answer is B. 42.