A display has
\[6\] packs of marbles with a total mass of
\[629\,\text{g}\]. The packaging of each pack has a mass of
\[\dfrac{2}{3}\,\text{g}\] and each marble has a mass of
\[4\dfrac{1}{2}\,\text{g}\].
Which equation can we use to determine
\[m\], the number of marbles per pack?
Choose 1 answer:
Choose 1 answer:
(Choice A)
\[6\cdot 4\dfrac{1}{2}m+\dfrac{2}{3}=629\]
A
\[6\cdot 4\dfrac{1}{2}m+\dfrac{2}{3}=629\]
(Choice B)
\[6m\left(4\dfrac{1}{2}+\dfrac{2}{3}\right)=629\]
B
\[6m\left(4\dfrac{1}{2}+\dfrac{2}{3}\right)=629\]
(Choice C)
\[6m+4\dfrac{1}{2}+\dfrac{2}{3}=629\]
C
\[6m+4\dfrac{1}{2}+\dfrac{2}{3}=629\]
(Choice D)
\[6\left(4\dfrac{1}{2}m+\dfrac{2}{3}\right)=629\]
D
\[6\left(4\dfrac{1}{2}m+\dfrac{2}{3}\right)=629\]
\[6\] packs of marbles with a total mass of
\[629\,\text{g}\]. The packaging of each pack has a mass of
\[\dfrac{2}{3}\,\text{g}\] and each marble has a mass of
\[4\dfrac{1}{2}\,\text{g}\].
Which equation can we use to determine
\[m\], the number of marbles per pack?
Choose 1 answer:
Choose 1 answer:
(Choice A)
\[6\cdot 4\dfrac{1}{2}m+\dfrac{2}{3}=629\]
A
\[6\cdot 4\dfrac{1}{2}m+\dfrac{2}{3}=629\]
(Choice B)
\[6m\left(4\dfrac{1}{2}+\dfrac{2}{3}\right)=629\]
B
\[6m\left(4\dfrac{1}{2}+\dfrac{2}{3}\right)=629\]
(Choice C)
\[6m+4\dfrac{1}{2}+\dfrac{2}{3}=629\]
C
\[6m+4\dfrac{1}{2}+\dfrac{2}{3}=629\]
(Choice D)
\[6\left(4\dfrac{1}{2}m+\dfrac{2}{3}\right)=629\]
D
\[6\left(4\dfrac{1}{2}m+\dfrac{2}{3}\right)=629\]
Answers
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im coming back to georiga connections
so whats the answer a b c or d
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