Question

A person falls in water at 0 C. After 30 min in the water, he/she suffers from hypothermia, as their body temp drops to 30 C. Since we are water.... we assume the heat capacity is 4.18 J/g/C. 180 Kcal of energy is required to raise the persons temp to 40 C. I need to find the mass.

You use Q=mc dT but I'm confused about temperature?

I also know that 180 kcal is 753 120 J.

What do we use for dT.. is it 40-30?

Answer 1

The heat capacity 0f 4.18 J/g.ºC is equivalent to 1.00 cal/g.ºC or 1.00kcal/kg.ºC

180kcal = (1.00kcal/kg.ºC)(m)(10.0ºC)

Solve for m

Answer 2

sweet thanks GK!