Asked by SWETA
The sides of a right angled triangle are x,x+1 and x+2.find x,Am not gettin the right answer.
Being a right triangle, x^2 + (x + 1)^2 = (x + 2)^2.
Expanding and simplifying, yields x^2 -- 2x - 3 = 0.
Factoring or the quadratic equation will lead you to the smallest Pythagorean Triple triangle with sides of 3, 4 and 5.
Being a right triangle, x^2 + (x + 1)^2 = (x + 2)^2.
Expanding and simplifying, yields x^2 -- 2x - 3 = 0.
Factoring or the quadratic equation will lead you to the smallest Pythagorean Triple triangle with sides of 3, 4 and 5.
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