The sum of two number is 18 .five times the first number subtracted from four over seven of the second number is 14 .find the number

Answer 1

Let's call the first number x and the second number y.

According to the problem, the sum of these two numbers is 18:
x + y = 18 ----(1)

The second part of the problem states that "five times the first number subtracted from four over seven of the second number is 14":
(4/7)y - 5x = 14 ----(2)

Now, we have two equations with two unknowns. We can solve this system of equations by substitution or elimination.

Using substitution, we can solve equation (1) for x:
x = 18 - y

Substituting this value of x into equation (2), we get:
(4/7)y - 5(18 - y) = 14

Expanding and simplifying the equation:
(4/7)y - 90 + 5y = 14

Combining like terms:
(4/7)y + 5y = 14 + 90

Multiplying by 7 to eliminate the fractions:
4y + 35y = 98 + 630

39y = 728

Dividing both sides by 39:
y = 728/39

Simplifying:
y ≈ 18.67

Now, we can substitute this value of y back into equation (1) to find x:
x + 18.67 = 18

Subtracting 18.67 from both sides:
x = 18 - 18.67

Simplifying:
x ≈ -0.67

Therefore, the first number is approximately -0.67 and the second number is approximately 18.67.