Asked by Sujan
There is a number between 10 and 100. The number is 8 times the sum of its digit.If 45 is subtracted from it , the result is number formed by interchanging its digit.Find the number.
soln
Let the number be x , let the sumb be y
8x= y
so 8x/y - 45 = yx
soln
Let the number be x , let the sumb be y
8x= y
so 8x/y - 45 = yx
Answers
Answered by
Steve
I think you will have better luck working with the digits.
Let the number have the digits xy
So, its value is 10x+y. Now we have
10x+y = 8(x+y)
10x+y-45 = 10y+x
Now you can easily discover that the number is 72
Let the number have the digits xy
So, its value is 10x+y. Now we have
10x+y = 8(x+y)
10x+y-45 = 10y+x
Now you can easily discover that the number is 72
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