Asked by mysterychicken
2 more problems that I'm stuck on, please help-
1.A square floor has an area of 32 m^2. Find the length of a side to the nearest tenth of a meter.
2.The height of a parallelogram is half the length of its base. the parallelogram has an area of 67 cm^2. Find the height to the nearest tenth of a centimeter.
I just need to know how to solve these two step-by-step
Thanks
-MC
1.A square floor has an area of 32 m^2. Find the length of a side to the nearest tenth of a meter.
2.The height of a parallelogram is half the length of its base. the parallelogram has an area of 67 cm^2. Find the height to the nearest tenth of a centimeter.
I just need to know how to solve these two step-by-step
Thanks
-MC
Answers
Answered by
MsPJ
1. A square has sides the same length so to find the area, you would have x times x
So x^2 = 32 Find the square root of 32 and go one place to the right of the decimal, round if necessary.
2. The base of the figure would be x and since the height is two times that it would be 2x. To find area, length times width, so x times 2x. So 2x^2 = 67.
divide both sides by 2 so that x^2=33.5
Now, find the square root of 33.5, so out one number to the right of the decimal point (tenths) and round if necessary.
Plug them back in to the area formula
(length times width) to check your answers.
Hope this helps!
So x^2 = 32 Find the square root of 32 and go one place to the right of the decimal, round if necessary.
2. The base of the figure would be x and since the height is two times that it would be 2x. To find area, length times width, so x times 2x. So 2x^2 = 67.
divide both sides by 2 so that x^2=33.5
Now, find the square root of 33.5, so out one number to the right of the decimal point (tenths) and round if necessary.
Plug them back in to the area formula
(length times width) to check your answers.
Hope this helps!
Answered by
MathMate
1.A square floor has an area of 32 m^2. Find the length of a side to the nearest tenth of a meter.
Let the side of the floor be x, then
x<sup>2</sup>=32
x=sqrt(32)
Use the method suggested by Bob to calculate the square root:
5*5=25
6*6=36
A better estimate will be
5+(6-5)*(32-25)/(36-25)=5.6
compared to 5.657.
2.The height of a parallelogram is half the length of its base. the parallelogram has an area of 67 cm^2. Find the height to the nearest tenth of a centimeter.
Let h=height of parallelogram
then b=base = 2h
Area of parallelogram = 67 cm<sup>2</sup>
then
h*2h=67
h<sup>2</sup>=67/2=33.5
h=sqrt(33.5)
Again using interpolation to find the square root
5*5=25
6*6=36
h=5+(6-5)*(33.5-25)/(36-25)=5.8
compared to 5.788 to three places.
Let the side of the floor be x, then
x<sup>2</sup>=32
x=sqrt(32)
Use the method suggested by Bob to calculate the square root:
5*5=25
6*6=36
A better estimate will be
5+(6-5)*(32-25)/(36-25)=5.6
compared to 5.657.
2.The height of a parallelogram is half the length of its base. the parallelogram has an area of 67 cm^2. Find the height to the nearest tenth of a centimeter.
Let h=height of parallelogram
then b=base = 2h
Area of parallelogram = 67 cm<sup>2</sup>
then
h*2h=67
h<sup>2</sup>=67/2=33.5
h=sqrt(33.5)
Again using interpolation to find the square root
5*5=25
6*6=36
h=5+(6-5)*(33.5-25)/(36-25)=5.8
compared to 5.788 to three places.
Answered by
mysterychicken
Thank you guys :D
-MC
-MC
Answered by
mysterychicken
I found the answers, thanks to both of you:
1. 5.7m
2. 5.8cm
:D
-MC
1. 5.7m
2. 5.8cm
:D
-MC
Answered by
MathMate
Here's a link to the manual method, if you are interested. It is a little more difficult to work it out here because of the formatting limitations.
Answered by
MathMate
Oops, the finger is faster than the brain. Here's the link:
http://www.itl.nist.gov/div897/sqg/dads/HTML/squareRoot.html
http://www.itl.nist.gov/div897/sqg/dads/HTML/squareRoot.html
Answered by
mysterychicken
Thank you
-MC
-MC
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