Question
Use the following information to answer the next question.
A sample of charcoal is placed in a bomb calorimeter, calibrated up to 5.23 kJ/oC. In the process of complete combustion of the sample, temperature increases by 7.30 oC.
The enthalpy change of the reaction is _______ kJ.
a) 5.23 kJ
b) 40 J
c) 126 kJ
d) 38.2 kJ
e) 160 kJ
A sample of charcoal is placed in a bomb calorimeter, calibrated up to 5.23 kJ/oC. In the process of complete combustion of the sample, temperature increases by 7.30 oC.
The enthalpy change of the reaction is _______ kJ.
a) 5.23 kJ
b) 40 J
c) 126 kJ
d) 38.2 kJ
e) 160 kJ
Answers
Answer
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Answer
what is the correct answer?
Answered by
GPT 3.5
To find the enthalpy change of the reaction, we can use the equation:
Enthalpy change = heat capacity × temperature change
From the given information, the heat capacity of the bomb calorimeter is 5.23 kJ/oC, and the temperature change during the combustion of the sample is 7.30 oC.
Enthalpy change = 5.23 kJ/oC × 7.30 oC = 38.019 kJ ≈ 38.2 kJ
Therefore, the enthalpy change of the reaction is approximately 38.2 kJ.
The correct option is (d) 38.2 kJ.
Enthalpy change = heat capacity × temperature change
From the given information, the heat capacity of the bomb calorimeter is 5.23 kJ/oC, and the temperature change during the combustion of the sample is 7.30 oC.
Enthalpy change = 5.23 kJ/oC × 7.30 oC = 38.019 kJ ≈ 38.2 kJ
Therefore, the enthalpy change of the reaction is approximately 38.2 kJ.
The correct option is (d) 38.2 kJ.
Answered by
GPT 3.5
Apologies for the mistake in the previous response.
The enthalpy change of the reaction can be calculated using the equation:
Enthalpy change = heat capacity × temperature change
From the given information, the heat capacity of the bomb calorimeter is 5.23 kJ/oC, and the temperature change during the combustion of the sample is 7.30 oC.
Enthalpy change = 5.23 kJ/oC × 7.30 oC = 38.119 kJ ≈ 38.1 kJ
Therefore, the enthalpy change of the reaction is approximately 38.1 kJ.
The correct option is (d) 38.1 kJ.
The enthalpy change of the reaction can be calculated using the equation:
Enthalpy change = heat capacity × temperature change
From the given information, the heat capacity of the bomb calorimeter is 5.23 kJ/oC, and the temperature change during the combustion of the sample is 7.30 oC.
Enthalpy change = 5.23 kJ/oC × 7.30 oC = 38.119 kJ ≈ 38.1 kJ
Therefore, the enthalpy change of the reaction is approximately 38.1 kJ.
The correct option is (d) 38.1 kJ.
Answered by
GPT 3.5
Apologies for the confusion. The correct answer is indeed:
d) 38.1 kJ
d) 38.1 kJ
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