Question
A 3.25 g piece of gold is cooled from 20.5°C to 13.8°C. The specific heat capacity of gold is 0.129 J/g°C. How much heat is released?
Question 16 options:
a) 2.81 J
b) 2.80 J
c) 2.8 J
d) 5.78 J
e) 8.59 J
Question 16 options:
a) 2.81 J
b) 2.80 J
c) 2.8 J
d) 5.78 J
e) 8.59 J
Answers
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Answered by
GPT 3.5
The formula to calculate the amount of heat released is given by:
Q = m * c * ΔT
Where:
Q = heat released
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
In this case, the mass of the gold is 3.25 g, the specific heat capacity of gold is 0.129 J/g°C, and the change in temperature is (13.8°C - 20.5°C) = -6.7°C.
Plugging in these values into the formula:
Q = 3.25 g * 0.129 J/g°C * (-6.7°C)
Q ≈ -2.7727 J
Since heat is released, the value is negative. However, the question asks for the magnitude of the heat released, so we take the absolute value:
|Q| ≈ |-2.7727 J| ≈ 2.7727 J
So the answer is approximately 2.77 J, which is closest to option b) 2.80 J.
Q = m * c * ΔT
Where:
Q = heat released
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
In this case, the mass of the gold is 3.25 g, the specific heat capacity of gold is 0.129 J/g°C, and the change in temperature is (13.8°C - 20.5°C) = -6.7°C.
Plugging in these values into the formula:
Q = 3.25 g * 0.129 J/g°C * (-6.7°C)
Q ≈ -2.7727 J
Since heat is released, the value is negative. However, the question asks for the magnitude of the heat released, so we take the absolute value:
|Q| ≈ |-2.7727 J| ≈ 2.7727 J
So the answer is approximately 2.77 J, which is closest to option b) 2.80 J.
Answered by
GPT 3.5
I apologize for the error. Let's calculate the correct heat released.
Q = m * c * ΔT
Q = 3.25 g * 0.129 J/g°C * (-6.7°C)
Q ≈ -2.7568 J
Again, since we are looking for the magnitude of the heat released, we take the absolute value:
|Q| ≈ |-2.7568 J| ≈ 2.76 J
So the correct answer is approximately 2.76 J, which is closest to option c) 2.8 J.
Q = m * c * ΔT
Q = 3.25 g * 0.129 J/g°C * (-6.7°C)
Q ≈ -2.7568 J
Again, since we are looking for the magnitude of the heat released, we take the absolute value:
|Q| ≈ |-2.7568 J| ≈ 2.76 J
So the correct answer is approximately 2.76 J, which is closest to option c) 2.8 J.
Answered by
GPT 3.5
I apologize once again for the confusion. I made a mistake in my calculations. Let's recalculate the correct heat released.
Q = m * c * ΔT
Q = 3.25 g * 0.129 J/g°C * (13.8°C - 20.5°C)
Q ≈ 3.25 g * 0.129 J/g°C * (-6.7°C)
Q ≈ -2.919 J
Taking the absolute value:
|Q| ≈ |-2.919 J| ≈ 2.919 J
So the correct answer is approximately 2.919 J, which is closest to option a) 2.81 J.
Q = m * c * ΔT
Q = 3.25 g * 0.129 J/g°C * (13.8°C - 20.5°C)
Q ≈ 3.25 g * 0.129 J/g°C * (-6.7°C)
Q ≈ -2.919 J
Taking the absolute value:
|Q| ≈ |-2.919 J| ≈ 2.919 J
So the correct answer is approximately 2.919 J, which is closest to option a) 2.81 J.
Answered by
GPT 3.5
I apologize for the confusion. I made an error in my previous calculations. Let's recalculate the correct heat released.
Q = m * c * ΔT
Q = 3.25 g * 0.129 J/g°C * (13.8°C - 20.5°C)
Q ≈ 3.25 g * 0.129 J/g°C * (-6.7°C)
Q ≈ -2.419 J
Taking the absolute value:
|Q| ≈ |-2.419 J| ≈ 2.419 J
So the correct answer is approximately 2.419 J, which is closest to option c) 2.8 J. My apologies for the previous incorrect responses.
Q = m * c * ΔT
Q = 3.25 g * 0.129 J/g°C * (13.8°C - 20.5°C)
Q ≈ 3.25 g * 0.129 J/g°C * (-6.7°C)
Q ≈ -2.419 J
Taking the absolute value:
|Q| ≈ |-2.419 J| ≈ 2.419 J
So the correct answer is approximately 2.419 J, which is closest to option c) 2.8 J. My apologies for the previous incorrect responses.
Answered by
GPT 3.5
Apologies for the incorrect responses earlier. The correct answer is 2.419 J, which is closest to option c) 2.8 J.
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