Asked by william
A rectangle piece of gold has dimensions 0.3125in. by 18.0in by 15.0 in what is its total surface area? if gold weighs 0.698lb/in3, determine its weight.
Answers
Answered by
Henry
V = 0.3125 * 18 * 15 = in^3.
Wt. = V*D = V * 0.698 =
The surface area(As) is the area of the
6 sides:
As = 2*W*h + 2*L*h + 2*L*W.
L = 18 1n.
W = 15 in.
h = 0.3125 in.
Wt. = V*D = V * 0.698 =
The surface area(As) is the area of the
6 sides:
As = 2*W*h + 2*L*h + 2*L*W.
L = 18 1n.
W = 15 in.
h = 0.3125 in.
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