Twice Peter's age now is the same as three times his age two years ago. How old is Peter now?

Answer 1

Let's represent Peter's age now as "x".
Twice Peter's age now is 2*x.
Three times his age two years ago is 3*(x-2).
According to the problem, 2*x = 3*(x-2).
Expanding the equation, we get 2x = 3x - 6.
Subtracting 2x from both sides, we get 0 = 3x - 2x - 6.
Simplifying the equation, we get 0 = x - 6.
Adding 6 to both sides, we get 6 = x.
Therefore, Peter is 6 years old now.