Asked by Anonymous
John is 3 times as old as peter .in 6 years time john will be twice as old as peter will be . Determine their present ages
Answers
Answered by
Bosnian
J = Present John's age
P = Present Peter's age
John is 3 times as old as peter mean:
J = 3 P
After 6 years John will be J + 6 yrs old
Peter will be P + 6 yrs old
In 6 years time john will be twice as old as peter will be mean:
( J + 6 ) / ( P + 6 ) = 2
Replace J = 3 P in this equation.
( 3 P + 6 ) / ( P + 6 ) = 2
Multiply both sides by P + 6
3 P + 6 = 2 ∙ ( P + 6 )
3 P + 6 = 2 ∙ P + 2 ∙ 6
3 P + 6 = 2 P + 12
Subtract 2 P to both sides
3 P - 2 P + 6 = 2 P - 2 P + 12
P + 6 = 12
Subtract 6 to both sides
P + 6 - 6 = 12 - 6
P = 6 yrs old
J = 3 P = 3 ∙ 6 = 18 yrs old
Proof:
J / P = 18 / 6 = 3
( J + 6 ) / ( P + 6 ) = ( 18 + 6 ) / ( 6 + 6 ) = 24 / 12 = 2
P = Present Peter's age
John is 3 times as old as peter mean:
J = 3 P
After 6 years John will be J + 6 yrs old
Peter will be P + 6 yrs old
In 6 years time john will be twice as old as peter will be mean:
( J + 6 ) / ( P + 6 ) = 2
Replace J = 3 P in this equation.
( 3 P + 6 ) / ( P + 6 ) = 2
Multiply both sides by P + 6
3 P + 6 = 2 ∙ ( P + 6 )
3 P + 6 = 2 ∙ P + 2 ∙ 6
3 P + 6 = 2 P + 12
Subtract 2 P to both sides
3 P - 2 P + 6 = 2 P - 2 P + 12
P + 6 = 12
Subtract 6 to both sides
P + 6 - 6 = 12 - 6
P = 6 yrs old
J = 3 P = 3 ∙ 6 = 18 yrs old
Proof:
J / P = 18 / 6 = 3
( J + 6 ) / ( P + 6 ) = ( 18 + 6 ) / ( 6 + 6 ) = 24 / 12 = 2
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