Question
A student tries to lift up a 100lb rock. At the end of five minutes the rock hasn't moved. How much work (e=fxd) was done on the rock
Answers
Answer
If it took him 2 seconds to lift the rock, how much power (p=E/t) was needed?
Answer
Later his other brother lifts the rock to a height of 6 ft. How much work was done?
Answer
How many horsepower were used? (550 ft-lbs/sec=1 HP)
Answered by
GPT 3.5
Work (W) is defined as the force (F) applied on an object multiplied by the distance (d) the object moves in the direction of the force. In this case, the rock did not move, so the distance it moved (d) is zero. Therefore, the work done on the rock is zero.
Answered by
GPT 3.5
Power (P) is defined as the work (W) done per unit time (t). It is calculated using the formula:
Power = Work/Time
In this case, we just established that no work (W) was done on the rock since it did not move. Therefore, the work done is zero.
The time taken to lift the rock is given as 2 seconds, so we can substitute t = 2 seconds into the formula.
Power = 0 / 2 seconds = 0 watts
Therefore, no power was needed to lift the rock since no work was done on it.
Power = Work/Time
In this case, we just established that no work (W) was done on the rock since it did not move. Therefore, the work done is zero.
The time taken to lift the rock is given as 2 seconds, so we can substitute t = 2 seconds into the formula.
Power = 0 / 2 seconds = 0 watts
Therefore, no power was needed to lift the rock since no work was done on it.
Answered by
GPT 3.5
To calculate the work done in lifting the rock to a height of 6 feet, we need to know the force applied and the distance over which the force was applied.
The work done (W) is calculated using the formula:
W = F * d
where F is the force applied and d is the distance covered.
In this case, the force applied will still be equal to the weight of the rock, which is 100 pounds.
The distance covered is the height to which the rock was lifted, which is 6 feet.
So, we can substitute F = 100 pounds and d = 6 feet into the formula:
W = 100 pounds * 6 feet = 600 foot-pounds
Therefore, the work done in lifting the rock to a height of 6 feet is 600 foot-pounds.
The work done (W) is calculated using the formula:
W = F * d
where F is the force applied and d is the distance covered.
In this case, the force applied will still be equal to the weight of the rock, which is 100 pounds.
The distance covered is the height to which the rock was lifted, which is 6 feet.
So, we can substitute F = 100 pounds and d = 6 feet into the formula:
W = 100 pounds * 6 feet = 600 foot-pounds
Therefore, the work done in lifting the rock to a height of 6 feet is 600 foot-pounds.
Answered by
GPT 3.5
To determine the horsepower used, we need to convert the work done in foot-pounds to horsepower.
1 horsepower is equal to 550 foot-pounds per second.
Given that the work done in lifting the rock is 600 foot-pounds, we can divide it by 550 to get the equivalent horsepower:
600 foot-pounds / 550 foot-pounds per second = 1.09 horsepower
Therefore, approximately 1.09 horsepower were used to lift the rock to a height of 6 feet.
1 horsepower is equal to 550 foot-pounds per second.
Given that the work done in lifting the rock is 600 foot-pounds, we can divide it by 550 to get the equivalent horsepower:
600 foot-pounds / 550 foot-pounds per second = 1.09 horsepower
Therefore, approximately 1.09 horsepower were used to lift the rock to a height of 6 feet.
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