Asked by kelly
how many grams of NH4Cl are required to prepare 250 mL of .122 M NH4Cl solution?
I set this up using the molarity equation and the part that I was missing is moles. So I divided the 0.122 by .25 L and got .031 mol.
Then I took that and multiplied it by the molar mass of NH4Cl and got it wrong.
How do I do this problem?
I set this up using the molarity equation and the part that I was missing is moles. So I divided the 0.122 by .25 L and got .031 mol.
Then I took that and multiplied it by the molar mass of NH4Cl and got it wrong.
How do I do this problem?
Answers
Answered by
DrBob222
What you did looks ok to me. 1.72 g?It could be that you rounded the 0.0305 to 0.031 too soon. You are allowed three significant figures so I would use 0.0305 for the moles required.
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