Asked by Jennifer

How many grams of dry NH4Cl need to be added to 1.80L of 0.200M solution of ammonia,NH3, to prepare a buffer that has a pH of 8.69? Kb for ammonia is 1.8*10^-5
Answered by DrBob222
Use the Henderson-Hasselbalch equation.
pH = pKa + log[(base)/(acid)]
You know pKa for NH3 (you have Kb listed but pKa = 14-pKb), you know pH, and you know (base). Calculate (acid), which is the NH4Cl, and go from concn to moles to grams. Post your work if get stuck.
Answered by Jennifer
thankyou it helped
Answered by Anonymous
im a ninja
Answered by Pookali
Can u do the steps please with the numbers
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