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If 20 g KCl is dissolved in 100g of water at 20 degrees C, is the solution unsaturated, saturated, or supersaturated?Asked by kate
If 20 g KCL is dissolved in 100g of water at 20 degrees C, is the solution unsaturated, saturated, or supersaturated?
Answers
Answered by
PC
If you google "potassium chloride Wiki", you will find somewhere the solubility of KCl as 34.4 g/100 ml. of water at 20 degrees C.
Refering to your previous question on saturated solution, you will find a definition of solubility, you should be able to tell if 20 g of KCl in 100 g of water is unsaturated or saturated.
Recall that the definition of
"saturated solution"
is
"A solution in which the maximum amount of solvent has been dissolved."
Note: water weighs (almost exactly) 1 g per ml.
Refering to your previous question on saturated solution, you will find a definition of solubility, you should be able to tell if 20 g of KCl in 100 g of water is unsaturated or saturated.
Recall that the definition of
"saturated solution"
is
"A solution in which the maximum amount of solvent has been dissolved."
Note: water weighs (almost exactly) 1 g per ml.
Answered by
kate
so it is unsaturated
Answered by
bobpursley
http://www.saskschools.ca/curr_content/chem30_05/graphics/4_graphics/sol_curve.jpg
Answered by
kate
i think it is saturated
Answered by
bobpursley
I think you are not reading the graph, and are guessing. You are wrong.
Answered by
PC
Kate,
You'd have to read the graph, but concentrate on the line that says KCl. The x-axis represents the temperature, and the y-axis represents the maximum number of grams of solute (KCl) that dissolves in water. This value represents the saturation point. Any solution containing less than this quantity is unsaturated.
Now, can you give it another try?
You'd have to read the graph, but concentrate on the line that says KCl. The x-axis represents the temperature, and the y-axis represents the maximum number of grams of solute (KCl) that dissolves in water. This value represents the saturation point. Any solution containing less than this quantity is unsaturated.
Now, can you give it another try?
Answered by
kate
unsaturated
Answered by
PC
Excellent, Kate!
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