Asked by Zach
0.250 g KCN is dissolved in 50 mL of water, and added to 2 mL of NaOH then mixed with 48mL of water. What is the molar concentration of KCN?
I am stuck on this question.
So far I have:
0.250gKCN/0.050L= 5M(g/L)
Moles of KCN: 5M = mol/0.05L = 0.25mol KCN
I am not sure exactly where to go from here or if I am on the right track. The addition of NaOH threw me off. If you can point me in the right direction it would be much appreciated.
I am stuck on this question.
So far I have:
0.250gKCN/0.050L= 5M(g/L)
Moles of KCN: 5M = mol/0.05L = 0.25mol KCN
I am not sure exactly where to go from here or if I am on the right track. The addition of NaOH threw me off. If you can point me in the right direction it would be much appreciated.
Answers
Answered by
DrBob222
Do you want concn in M or g/L. I will assume you want molarity = M
mols KCN = grams/molar mass KCN = ?
Then ?mols/0.052 L = ? mols/L = M KCN. The NaOH just adds 2 mL to the total volume.
mols KCN = grams/molar mass KCN = ?
Then ?mols/0.052 L = ? mols/L = M KCN. The NaOH just adds 2 mL to the total volume.
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