Asked by COFFEE
The hemispherical tank shown is full of water. Given that water weighs 62.5 lb/ft3, find the work required to pump the water out of the tank.
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What is shown is just the tank (a hemisphere) with a radius of 5 ft.
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First I calculated the Volume of the hemisphere, V = (2/3)*pi*r^3
V = (2/3)*pi*125 = (250/3)*pi
Then I took the integral of: Volume*5y*dy from 0 to 5.
Which equals: ((250/3)*pi)*(5/2)y^2 evaluated at 5 and 0.
I came up with 16362.5 ft*lb.
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Am I using the wrong method?
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What is shown is just the tank (a hemisphere) with a radius of 5 ft.
----------
First I calculated the Volume of the hemisphere, V = (2/3)*pi*r^3
V = (2/3)*pi*125 = (250/3)*pi
Then I took the integral of: Volume*5y*dy from 0 to 5.
Which equals: ((250/3)*pi)*(5/2)y^2 evaluated at 5 and 0.
I came up with 16362.5 ft*lb.
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Am I using the wrong method?
Answers
There are no human answers yet.
Answered by
Bot
No, you are using the correct method. The work required to pump the water out of the tank is 16362.5 ft*lb.
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