Asked by shilpi
a hemispherical tank full of water is emptied by a pipe at the rate of 25/7 litres/second.How much time will it take to make the tank half empty,if the tank is 3 metres in diameter?
Answers
Answered by
Steve
v = 4/3 pi r^3, so the tank can hold
1/2 * 4/3 * pi * (3/2)^3 = 7.07 m^3 of water
So, it will take
7.07 m^3 / (25/7 L/s) to drain
I'll let you do the conversion from m^3 to liters.
1/2 * 4/3 * pi * (3/2)^3 = 7.07 m^3 of water
So, it will take
7.07 m^3 / (25/7 L/s) to drain
I'll let you do the conversion from m^3 to liters.
Answered by
Anonymous
16.5minutes
Answered by
Sahil
Given, diameter = 3m
So radius = 3/2 m
Rate at which air is pumped is 25/7 liter per second
Volume of tank = 2/3 πr^3 = 99/14m^3
=99000/14 liters
Since 1 liter of air can be pumped in 7/25 sec
Therefore , 99000/14 liter of air can be pumped in 7/25×99000/14 sec
= 1980 sec
= 33 min
So radius = 3/2 m
Rate at which air is pumped is 25/7 liter per second
Volume of tank = 2/3 πr^3 = 99/14m^3
=99000/14 liters
Since 1 liter of air can be pumped in 7/25 sec
Therefore , 99000/14 liter of air can be pumped in 7/25×99000/14 sec
= 1980 sec
= 33 min
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