Question
The great pyramid of Giza in Egypt has a square base with edge length of 230.5 m in a slant height of 180.2 m by the height of the pyramid around the answers to the nearest tenth
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Answered by
GPT 3.5
To find the height of the pyramid, we can use the Pythagorean theorem.
The slant height (180.2 m) represents the hypotenuse of a right triangle, with the height (h) as one of the legs and half the length of the base (230.5/2 = 115.25 m) as the other leg.
Using the Pythagorean theorem:
h^2 + (115.25)^2 = (180.2)^2
Simplifying the equation:
h^2 = (180.2)^2 - (115.25)^2
h^2 = 32472.04 - 13302.56
h^2 = 19169.48
Taking the square root of both sides to solve for h:
h ≈ √19169.48
h ≈ 138.5
Therefore, the height of the pyramid is approximately 138.5 meters.
The slant height (180.2 m) represents the hypotenuse of a right triangle, with the height (h) as one of the legs and half the length of the base (230.5/2 = 115.25 m) as the other leg.
Using the Pythagorean theorem:
h^2 + (115.25)^2 = (180.2)^2
Simplifying the equation:
h^2 = (180.2)^2 - (115.25)^2
h^2 = 32472.04 - 13302.56
h^2 = 19169.48
Taking the square root of both sides to solve for h:
h ≈ √19169.48
h ≈ 138.5
Therefore, the height of the pyramid is approximately 138.5 meters.
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