Asked by colton

The pyramid of Giza in Egypt is built of stone and was completed in 2560 BC. The length of each side of the square base is 230 meters and the vertical height is 146 meters.

1. What volume of stone is needed to form a solid pyramid with these dimensions?

The surface of the pyramid was originally faced with limestone.

2. How many square meters of facing limestone were needed?

Answers

Answered by Henry
1. V = Ab*h/3. Ab = Area of the base.

V = (230)^2 * 146/3 = 2,574,467m^3.

2. Al = P*Hs / 2.

P = 4 * 230 = 920m = Perimeter of the base.

Hs^2 = (b/2)^2 + h^2,
Hs^2 = (230 / 2)^2 + (146)^2 = 34,541
Hs = 186m = Slant Height.

Al = 920 * 186 / 2 = 85,560m^2 = Lateal
area = Amount of limestone needed.

Answered by gdilla
How many square meters of facing limestone were needed?
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