Question
How many grams of butyric acid contain 3.28 x 1023 atoms of oxygen?
Express your answer to three significant figures and include the appropriate units.
Express your answer to three significant figures and include the appropriate units.
Answers
GPT 3.5
To determine the amount of butyric acid that contains 3.28 x 10^23 atoms of oxygen, we need to use the conversion factor between the two.
1 mole of butyric acid (C4H8O2) contains 2 moles of oxygen atoms (O).
The molar mass of butyric acid is:
(4*12.01 g/mol) + (8*1.01 g/mol) + (2*16.00 g/mol) = 88.11 g/mol
The molar mass of oxygen is 16.00 g/mol.
Therefore, 1 mole of butyric acid contains (2*16.00) = 32.00 grams of oxygen.
Using this information, we can set up the following conversion factor:
(32.00 g of O / 1 mol of butyric acid) x (1 mol of butyric acid / 6.022 x 10^23 atoms of O) = 5.31 x 10^-24 g of O per atom
To find the amount of butyric acid that contains 3.28 x 10^23 atoms of oxygen, we can use the inverse of this conversion factor:
(3.28 x 10^23 atoms of O) x (5.31 x 10^-24 g of O per atom) = 1.74 g of butyric acid
Therefore, 3.28 x 10^23 atoms of oxygen are contained in 1.74 grams (rounded to three significant figures) of butyric acid.
1 mole of butyric acid (C4H8O2) contains 2 moles of oxygen atoms (O).
The molar mass of butyric acid is:
(4*12.01 g/mol) + (8*1.01 g/mol) + (2*16.00 g/mol) = 88.11 g/mol
The molar mass of oxygen is 16.00 g/mol.
Therefore, 1 mole of butyric acid contains (2*16.00) = 32.00 grams of oxygen.
Using this information, we can set up the following conversion factor:
(32.00 g of O / 1 mol of butyric acid) x (1 mol of butyric acid / 6.022 x 10^23 atoms of O) = 5.31 x 10^-24 g of O per atom
To find the amount of butyric acid that contains 3.28 x 10^23 atoms of oxygen, we can use the inverse of this conversion factor:
(3.28 x 10^23 atoms of O) x (5.31 x 10^-24 g of O per atom) = 1.74 g of butyric acid
Therefore, 3.28 x 10^23 atoms of oxygen are contained in 1.74 grams (rounded to three significant figures) of butyric acid.