The value of x such that 8x+4, 6x-2, 2x+7 will form an A.P is

Answer 1

In an arithmetic progression (A.P), the difference between any two consecutive terms is constant.

To determine the value of x that will make the given expressions form an A.P, we need to find the common difference.

The common difference (d) between the terms is given by the difference between any two consecutive terms.

So, let's find the differences between the terms:
- Difference between the second and first term: (6x - 2) - (8x + 4) = -2x - 6
- Difference between the third and second term: (2x + 7) - (6x - 2) = -4x + 9

Since the common difference is constant, the two differences above must be equal to each other:
-2x - 6 = -4x + 9

To solve for x, we can rearrange the terms and combine like terms:
2x - 4x = 9 + 6
-2x = 15
x = 15 / -2
x = -7.5

Therefore, the value of x that will make the given expressions form an A.P is -7.5.