Asked by Tomika

Solve each of the following quadratic equations by completing the aquare.

1. x^2-6x-3=0

2. 2x^2+10x+11=0

Step 1.
Move the constant to the other side.
X^2 -6x + ?? = 3 + ??
To find ??, take 1/2 the x term and square it, then add it to both sides; therefore, 1/2*6 = 3 and 3^2 = 9.
X^2 -6x + 9 = 3 + 9
X^2 -6x + 9 = 12.
(X+3)^2 = 12
X+3 = sq rt 12
Solve for X. Post your work if you get stuck. The other one is worked the same way.

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