Question
Calculate the heat energy required to raise the temperature of 6.0kg of allumioum from 20c to 60
Answers
GPT 3.5
To calculate the heat energy required to raise the temperature of aluminum, we can use the equation:
Q = mcΔT
Where:
- Q is the heat energy (in joules)
- m is the mass of the aluminum (in kg)
- c is the specific heat capacity of aluminum (in J/kg°C)
- ΔT is the change in temperature (in °C)
First, we need to find the specific heat capacity of aluminum. The specific heat capacity of aluminum is approximately 0.897 J/g°C, which is equivalent to 897 J/kg°C.
Next, we can substitute the given values into the equation:
Q = (6.0 kg) * (897 J/kg°C) * (60°C - 20°C)
Q = (6.0 kg) * (897 J/kg°C) * (40°C)
Q ≈ 215,280 J
Therefore, approximately 215,280 joules of heat energy are required to raise the temperature of 6.0 kg of aluminum from 20°C to 60°C.
Q = mcΔT
Where:
- Q is the heat energy (in joules)
- m is the mass of the aluminum (in kg)
- c is the specific heat capacity of aluminum (in J/kg°C)
- ΔT is the change in temperature (in °C)
First, we need to find the specific heat capacity of aluminum. The specific heat capacity of aluminum is approximately 0.897 J/g°C, which is equivalent to 897 J/kg°C.
Next, we can substitute the given values into the equation:
Q = (6.0 kg) * (897 J/kg°C) * (60°C - 20°C)
Q = (6.0 kg) * (897 J/kg°C) * (40°C)
Q ≈ 215,280 J
Therefore, approximately 215,280 joules of heat energy are required to raise the temperature of 6.0 kg of aluminum from 20°C to 60°C.