Asked by ddf
the amount of heat energy required to convert 5g of ice at 0 degree centigrade into water at 40 degree centigrade is
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Answered by
Anonymous
Q= L m+ cm•Δt = m(L+c•Δt)=
=0.005(334000+4184•40)=1678.2 J
=0.005(334000+4184•40)=1678.2 J
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