Question
                Solve the system of equations.
8x−4y=−28
 
2x−6y=8
(1 point)
Responses
(7, 1)
left parenthesis 7 comma 1 right parenthesis
(−5,−3)
left parenthesis negative 5 comma negative 3 right parenthesis
(−2, 3)
left parenthesis negative 2 comma 3 right parenthesis
(−4,−1)
            
        8x−4y=−28
2x−6y=8
(1 point)
Responses
(7, 1)
left parenthesis 7 comma 1 right parenthesis
(−5,−3)
left parenthesis negative 5 comma negative 3 right parenthesis
(−2, 3)
left parenthesis negative 2 comma 3 right parenthesis
(−4,−1)
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT 3.5
            
    To solve the system of equations, we can use either substitution or elimination method.
Let's use the elimination method:
First, let's multiply the second equation by 4 to eliminate the x term:
4(2x - 6y) = 4(8)
8x - 24y = 32
Now we have two equations:
8x - 4y = -28
8x - 24y = 32
Next, subtract the first equation from the second equation:
(8x - 24y) - (8x - 4y) = 32 - (-28)
-20y = 60
y = -3
Now substitute the value of y back into one of the original equations:
8x - 4(-3) = -28
8x + 12 = -28
8x = -40
x = -5
Therefore, the solution to the system of equations is (-5, -3).
    
Let's use the elimination method:
First, let's multiply the second equation by 4 to eliminate the x term:
4(2x - 6y) = 4(8)
8x - 24y = 32
Now we have two equations:
8x - 4y = -28
8x - 24y = 32
Next, subtract the first equation from the second equation:
(8x - 24y) - (8x - 4y) = 32 - (-28)
-20y = 60
y = -3
Now substitute the value of y back into one of the original equations:
8x - 4(-3) = -28
8x + 12 = -28
8x = -40
x = -5
Therefore, the solution to the system of equations is (-5, -3).
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