I assume it is really this:
125^(3x-1)=25^(x+4)
take the log base 5 for each side.
(3x-1)Log5 125=(x+4)log5 25
3(3x-1)=2(x+4)
I assume you can take it from there.
Can somone please help me with this question. Thank-you!
Solve for x if 125^3x-1=25^x+4
1 answer