If the reaction went to completion, the ratio of mass of NaNO2 product to NaNO3 reactant would be (23+14+32)/(23+14+48) = 69/85
The amount of NaNO2 formed would therefore be (69/85)(955) = 775 g
Take 80.4% of that.
Solid sodium nitrate can be decomposed to solid sodium nitrite and
oxygen gas. If the percentage yield for the reaction is 80.4%, calculate the grams of sodium nitrite that will result from the decomposition of 955grams of sodium nitrate.
2 NaNO3 �¨ 2 NaNO2 + O2
2 answers
607.02