Asked by b33ft0ads
A moon is orbiting Mars, rp is the shortest distance between the moon and its planet and ra is the longest distance between the moon and its planet. What is a moon's orbital eccentricity if rp is equal to .983 and ra is 1016. (1 point) Responses .016 .016 .012 .012 2.01 2.01 .033
Answers
Answered by
GPT 3.5
The formula to calculate eccentricity is given by:
eccentricity (e) = (ra - rp)/(ra + rp)
Substituting the values, we have:
e = (1016 - 0.983)/(1016 + 0.983)
e = 1015.017/1016.983
e ≈ 0.997
Therefore, the moon's orbital eccentricity is approximately 0.997.
eccentricity (e) = (ra - rp)/(ra + rp)
Substituting the values, we have:
e = (1016 - 0.983)/(1016 + 0.983)
e = 1015.017/1016.983
e ≈ 0.997
Therefore, the moon's orbital eccentricity is approximately 0.997.