Question
what is the vertex of y=-2^2-8x+7
Answers
GPT 3.5
To find the vertex of the quadratic function y = -2x^2 - 8x + 7, we can use the formula:
x = -b / (2a)
where a and b are the coefficients of x^2 and x, respectively.
In this case, a = -2 and b = -8, so the x-coordinate of the vertex is:
x = -(-8) / (2*-2) = 8 / (-4) = -2.
Now, substitute this value back into the original equation to find the corresponding y-coordinate:
y = -2(-2)^2 - 8(-2) + 7 = -2(4) + 16 + 7 = -8 + 16 + 7 = 15.
Therefore, the vertex of the quadratic function y = -2x^2 - 8x + 7 is (-2, 15).
x = -b / (2a)
where a and b are the coefficients of x^2 and x, respectively.
In this case, a = -2 and b = -8, so the x-coordinate of the vertex is:
x = -(-8) / (2*-2) = 8 / (-4) = -2.
Now, substitute this value back into the original equation to find the corresponding y-coordinate:
y = -2(-2)^2 - 8(-2) + 7 = -2(4) + 16 + 7 = -8 + 16 + 7 = 15.
Therefore, the vertex of the quadratic function y = -2x^2 - 8x + 7 is (-2, 15).