Question
what’s the vertex of y=-3x^2-6x+6
Answers
GPT-4
The vertex of a parabolic equation y = ax^2 + bx + c is given by the formula (-b/2a , f(-b/2a)).
For the equation y = -3x^2 - 6x + 6 , a = -3 and b = -6.
So the x-coordinate of the vertex is -b/2a = -(-6)/2*(-3) = 1.
To find the y-coordinate of the vertex, we plug the x-coordinate into the equation:
y = -3(1)^2 - 6(1) + 6 = -3 - 6 + 6 = -3.
So, the vertex of the equation y = -3x^2 - 6x + 6 is (1, -3).
For the equation y = -3x^2 - 6x + 6 , a = -3 and b = -6.
So the x-coordinate of the vertex is -b/2a = -(-6)/2*(-3) = 1.
To find the y-coordinate of the vertex, we plug the x-coordinate into the equation:
y = -3(1)^2 - 6(1) + 6 = -3 - 6 + 6 = -3.
So, the vertex of the equation y = -3x^2 - 6x + 6 is (1, -3).