To find the number of terms in a sequence, we need to determine the pattern and the last term.
The pattern in this sequence is that each term is double the previous term.
Starting with 1/128 and doubling it, we find the following terms:
1/128, 1/64, 1/32, 1/16, 1/8, 1/4, 1/2, 1, 2, 4, 8, 16, 32, 64
The last term is 64.
To find the number of terms in this sequence, we need to count how many terms there are from 1/128 to 64.
If we continue to double the terms from 1/128, we will eventually reach 64. We only need to count how many times we need to double 1/128 to get to 64.
In each doubling, we multiply by 2. So, if we divide 64 by 1/128, we can find out how many times we need to double 1/128 to get to 64:
64 / (1/128) = 64 * 128 = 8192
Therefore, there are 8192 terms in this sequence.
Number of terms in this sequence 1/128, 1/64,1/32,.........,32,64 is
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