Question

Suppose f(x)=7x-2 and g(x)= sqrt x^2-2x+9

(f(g(x))=

(f(g(x)(-2)=

Answer 1

To find (f(g(x)), we plug the expression for g(x) into f(x):

f(g(x)) = 7(g(x)) - 2

Now, substituting g(x) in place of x:

f(g(x)) = 7(sqrt(x^2 - 2x + 9)) - 2

To find (f(g(x))(-2), we substitute this expression into -2:

(f(g(x))(-2) = -2 * (7(sqrt(x^2 - 2x + 9)) - 2)

Simplifying further:

(f(g(x))(-2) = -14(sqrt(x^2 - 2x + 9)) + 4