Asked by jeff
2.8 g of the nonvolatile solute sucrose (C12H22O11) is added to 517 g of water at 25oC. What will be the partial pressure of the water vapor over this solution?
Answers
Answered by
DrBob222
Isn't partial pressure =
P = P<sup>o</sup>*X<sub>o</sub> ?
So convert g of solvent to mole fraction and multiply by the normal vapor pressure of the solvent. Post your work if you get stuck.
P = P<sup>o</sup>*X<sub>o</sub> ?
So convert g of solvent to mole fraction and multiply by the normal vapor pressure of the solvent. Post your work if you get stuck.
Answered by
jeff
So 2.8 converted to mols and then divided by 517? And multiplied by 25oC?
Answered by
DrBob222
No.
mole fraction of solvent =
moles solvent/(moles solvent + moles solute)
mole fraction of solvent =
moles solvent/(moles solvent + moles solute)
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