Question
When 3.78 g of nonvolatile solute is dissolved in 300.0 g of water, the freezing point depression is 0.646 o C. Calculate the molar mass of the solute. The cryoscopic constant of water is 1.86 K kg mol -1.
When 3.78 g of nonvolatile solute is dissolved in 300.0 g of water, the freezing point depression is 0.646 o C. Calculate the molar mass of the solute. The cryoscopic constant of water is 1.86 K kg mol -1.
DeltaTf= molality*Kf
.646=molrSolute/.3 * 1.86
.646=3.78/molmass/.3 * 1.86
solve for molmass.
When 3.78 g of nonvolatile solute is dissolved in 300.0 g of water, the freezing point depression is 0.646 o C. Calculate the molar mass of the solute. The cryoscopic constant of water is 1.86 K kg mol -1.
DeltaTf= molality*Kf
.646=molrSolute/.3 * 1.86
.646=3.78/molmass/.3 * 1.86
solve for molmass.
Answers
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