Question

A very long wire carries a current of 2.30 A and is bent into the shape seen below. One part is exactly half a circle with a radius of 4.60 cm, and the rest is _______.

Answer 1

To determine the shape of the wire, we need to analyze the given information.

The wire is bent into the shape seen below, with one part being a half-circle with a radius of 4.60 cm:

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Let's call the length of the wire in the half-circle part L1. In a half-circle, the circumference is equal to half the total circumference of a complete circle. We can calculate L1 using the formula for the circumference of a circle:

C1 = πd

Since the diameter (d) of the circle is twice the radius (r), we have:

L1 = π(2r) / 2 = πr

Given that the radius r is 4.60 cm, we can calculate L1:

L1 = π * 4.60 cm ≈ 14.44 cm

Now we need to determine what shape makes up the remaining length of the wire. Since the wire is bent into this shape, and one part forms a semicircle, we can imply that the remaining part takes a straight line, parallel to the horizontal part of the semicircle, as shown:

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Therefore, the remaining part is a straight line segment.