Question

An infinitely long wire carries a current I=100A. Below the wire a rod of length L=10cm is forced to move at a constant speed v=5m/s along horizontal conducting rails. The rod and rails form a conducting loop. The rod has resistance of R=0.4ohms. The rails have neglibible resistance. The rod and rails are a distance a=10mm from the wire and in its non-uniform magnetic field as shown. What is the magnitude of the emf induced in the loop?

Answer 1

first, ampere's law

2PI * r * B=mu*current

solve that for B

Now Faradays law.

change Area/time= speed*.1m

EMF=B*speed*.1

check my thinking.

Notice in the description, r=a as I understand the "written" diagram.

Answer 2

hai @ Bobpursely i try with this hint u give us and i used mu=1.256*10^-6 but is not work , did u got green check using above formula ????? thanks !

Answer 3

0.001 V

Answer 4

Hello, can someone please explain the one with the thick metal slab???

Answer 5

really? is 0.001 the answer???

Answer 6

who have the answer?

Answer 7

0.001 is wrong @MARC , did u got green check with that value ??? plz help ???

Answer 8

that's what I thought, but then, the procedure indicated is not convincing.

Has anyone check the one with the 1mm diameter wire and current, which is the max B? I'm not sure how to calculate that.

Answer 9

hai any one got the ans of this
Two thin, infinitely long, parallel wires are lying on the ground a distance d=3cm apart. They carry a current Io=200A going into the page. A third thin, infinitely long wire with mass per unit length λ=5g/m carries current I going out of the page. What is the value of the current I in amps in this third wire if it is levitated above the first two wires at height h=10cm above them and at a horizontal position midway between them? plz help ???

Answer 10

anyone with this q:
A straight copper wire that is 1 milimeter in diameter carries a current of 20 miliamps. Whats the magnitude of the largest magnetic field created by this wire in Tesla?

I think B=uo.I/(2*pi*r)=8*10^-6

B at the perimeter, but I used r^2 instead of r, so I don't want to waste my last chance, anyone has tried that value? or feel like try it out and let me know if that is the correct value?

Answer 11

yup @flO That's correct ! so did u done for this question
Two thin, infinitely long, parallel wires are lying on the ground a distance d=3cm apart. They carry a current Io=200A going into the page. A third thin, infinitely long wire with mass per unit length λ=5g/m carries current I going out of the page. What is the value of the current I in amps in this third wire if it is levitated above the first two wires at height h=10cm above them and at a horizontal position midway between them? plz help ???

Answer 12

@mandela, thanks.

And yes, I found that question in another post, here's the number 1387146949.

By the way, are you done with the other questions?

Answer 13

Yep, 8*10*-6 is the answer.

A square loop of wire of side L with total resistance R moves at constant speed v into a region of uniform magnetic field B pointing perpendicular to the plane of the loop. What is the average current that is induced.

Iave=BL^2/R is that the answer???

Answer 14

Hello, so any idea for the original question???? Has anyone checked the answer of the problem?

Answer 15

Hello, I don't how I did it, but for the original question I got this emf value: 2.39*10^-6

Answer 16

wait, emf = 2.39*10^-4, which makes sense, 0.001 would be for a constant B, but this one vries

Answer 17

Is that the correct answer??

Answer 18

nobody did it??
Two thin, infinitely long, parallel wires are lying on the ground a distance d=3cm apart. They carry a current Io=200A going into the page. A third thin, infinitely long wire with mass per unit length λ=5g/m carries current I going out of the page. What is the value of the current I in amps in this third wire if it is levitated above the first two wires at height h=10cm above them and at a horizontal position midway between them? plz help ???

Please!

Answer 19

@ CUr 62.5

Answer 20

Thanks!