To find the height of the ball 4 seconds after it has been thrown, we need to substitute t = 4 into the equation h(t) = -16t^2 + 72t.
So, h(4) = -16(4)^2 + 72(4)
= -16(16) + 288
= -256 + 288
= 32
Therefore, the height of the ball 4 seconds after it has been thrown is 32 feet.
When a ball is thrown up into the air, the function h(t) = −16t^2 + 72t
gives the height h
in feet of the ball t
seconds after it has been thrown. Find the height of the ball 4 seconds after it has been thrown. (1 point)
Responses
4384
4384
48
48
32
32
288
1 answer