To find the combined mass of the two skyscrapers, you need to add their masses together.
The first skyscraper has a mass of 2.2×10^5 tons, and the second skyscraper has a mass of 3.7×10^5 tons.
Adding these two masses together, you get:
2.2×10^5 + 3.7×10^5 = 5.9×10^5
Therefore, the combined mass of the two skyscrapers is 5.9×10^5 tons.
A skyscraper has a mass of 2.2×105 tons. Another skyscraper in the same town has a mass of 3.7×105 tons. What is the combined mass, in tons, of the two skyscrapers? Use scientific notation to express your answer to 1 decimal place.
17 answers
What is the sum of 6.3×103 and 2.41×104 ? Use scientific notation to express your answer.
To find the sum of 6.3×10^3 and 2.41×10^4, you need to add the two numbers together.
6.3×10^3 + 2.41×10^4 = 6.3×10^3 + 24.1×10^3
To add these two numbers, the exponents need to be the same. Since 10^3 and 10^4 are both powers of 10, you can rewrite the expression as:
6.3×10^3 + 24.1×10^3 = (6.3 + 24.1)×10^3
Adding the coefficients, you get:
6.3 + 24.1 = 30.4
Therefore, the sum of 6.3×10^3 and 2.41×10^4 is:
30.4×10^3
Written in scientific notation, the sum is:
3.04×10^4
6.3×10^3 + 2.41×10^4 = 6.3×10^3 + 24.1×10^3
To add these two numbers, the exponents need to be the same. Since 10^3 and 10^4 are both powers of 10, you can rewrite the expression as:
6.3×10^3 + 24.1×10^3 = (6.3 + 24.1)×10^3
Adding the coefficients, you get:
6.3 + 24.1 = 30.4
Therefore, the sum of 6.3×10^3 and 2.41×10^4 is:
30.4×10^3
Written in scientific notation, the sum is:
3.04×10^4
An American football field has an area of 6.4×103 square yards. A Canadian football field is 3,350 square yards larger. What is the area of a Canadian football field? Write your answer in scientific notation to 2 decimal places
To find the area of the Canadian football field, you need to add 3,350 square yards to the area of the American football field.
The American football field has an area of 6.4×10^3 square yards, and the Canadian football field is 3,350 square yards larger.
Adding these two areas together, you get:
6.4×10^3 + 3,350 = 6.4×10^3 + 3.35×10^3
To add these two numbers, the exponents need to be the same. Since 10^3 and 10^3 are both powers of 10, you can rewrite the expression as:
6.4×10^3 + 3.35×10^3
Adding the coefficients, you get:
6.4 + 3.35 = 9.75
Therefore, the area of the Canadian football field is:
9.75×10^3 square yards
Written in scientific notation to 2 decimal places, the area of the Canadian football field is:
9.75×10^3 square yards
The American football field has an area of 6.4×10^3 square yards, and the Canadian football field is 3,350 square yards larger.
Adding these two areas together, you get:
6.4×10^3 + 3,350 = 6.4×10^3 + 3.35×10^3
To add these two numbers, the exponents need to be the same. Since 10^3 and 10^3 are both powers of 10, you can rewrite the expression as:
6.4×10^3 + 3.35×10^3
Adding the coefficients, you get:
6.4 + 3.35 = 9.75
Therefore, the area of the Canadian football field is:
9.75×10^3 square yards
Written in scientific notation to 2 decimal places, the area of the Canadian football field is:
9.75×10^3 square yards
A human hair has a diameter of about 4×10−3 inches. A fingernail is about 0.011 inches thicker. How thick is a fingernail? Write your answer as a decimal to 3 places
To find the thickness of a fingernail, you need to add the additional thickness of 0.011 inches to the diameter of a human hair.
The diameter of a human hair is about 4×10^(-3) inches, and a fingernail is about 0.011 inches thicker.
Adding these two dimensions together, you get:
4×10^(-3) + 0.011 = 4×10^(-3) + 11×10^(-3)
To add these two numbers, the exponents need to be the same. Since 10^(-3) and 10^(-3) are both negative powers of 10, you can rewrite the expression as:
4×10^(-3) + 11×10^(-3) = (4 + 11)×10^(-3)
Adding the coefficients, you get:
4 + 11 = 15
Therefore, the thickness of a fingernail is:
15×10^(-3) inches
Written as a decimal to 3 places, the thickness of a fingernail is:
0.015 inches
The diameter of a human hair is about 4×10^(-3) inches, and a fingernail is about 0.011 inches thicker.
Adding these two dimensions together, you get:
4×10^(-3) + 0.011 = 4×10^(-3) + 11×10^(-3)
To add these two numbers, the exponents need to be the same. Since 10^(-3) and 10^(-3) are both negative powers of 10, you can rewrite the expression as:
4×10^(-3) + 11×10^(-3) = (4 + 11)×10^(-3)
Adding the coefficients, you get:
4 + 11 = 15
Therefore, the thickness of a fingernail is:
15×10^(-3) inches
Written as a decimal to 3 places, the thickness of a fingernail is:
0.015 inches
Add 7.3 × 10^7 + 1.8 × 10^7
To add 7.3 × 10^7 and 1.8 × 10^7, the numbers need to have the same exponent.
Therefore, it becomes:
7.3 × 10^7 + 1.8 × 10^7 = (7.3 + 1.8) × 10^7
Performing the addition:
7.3 + 1.8 = 9.1
So, the sum is:
9.1 × 10^7
Therefore, it becomes:
7.3 × 10^7 + 1.8 × 10^7 = (7.3 + 1.8) × 10^7
Performing the addition:
7.3 + 1.8 = 9.1
So, the sum is:
9.1 × 10^7
The population of a city is given as 3.45×106 . A nearby city has a population of 1.3×105 . What is the sum of the populations of the two cities in scientific notation?
To find the sum of the populations of the two cities, you need to add their population values together.
The population of the first city is given as 3.45×10^6, and the population of the nearby city is 1.3×10^5.
Adding these two population values together, you get:
3.45×10^6 + 1.3×10^5
Since the exponents are already the same, you can simply add the coefficients:
3.45 + 1.3 = 4.75
Therefore, the sum of the populations of the two cities in scientific notation is:
4.75×10^6.
The population of the first city is given as 3.45×10^6, and the population of the nearby city is 1.3×10^5.
Adding these two population values together, you get:
3.45×10^6 + 1.3×10^5
Since the exponents are already the same, you can simply add the coefficients:
3.45 + 1.3 = 4.75
Therefore, the sum of the populations of the two cities in scientific notation is:
4.75×10^6.
An empty dump truck weighs about 2.8×105 pounds. How much does it weigh if 15,300 pounds of trash is added? The answer should be in scientific notation.
To find the weight of the dump truck after adding 15,300 pounds of trash, you need to add the additional weight to the initial weight.
The empty dump truck weighs about 2.8×10^5 pounds, and 15,300 pounds of trash is added.
Adding these two weights together, you get:
2.8×10^5 + 15,300
Since the coefficients have different units (pounds and pounds), there is no need to convert them.
Therefore, the weight of the dump truck after adding 15,300 pounds of trash, in scientific notation, is:
2.8×10^5 + 1.53×10^4 = 3.953×10^5 pounds.
The empty dump truck weighs about 2.8×10^5 pounds, and 15,300 pounds of trash is added.
Adding these two weights together, you get:
2.8×10^5 + 15,300
Since the coefficients have different units (pounds and pounds), there is no need to convert them.
Therefore, the weight of the dump truck after adding 15,300 pounds of trash, in scientific notation, is:
2.8×10^5 + 1.53×10^4 = 3.953×10^5 pounds.
The half-life of uranium-235 is 700,000,000 years. The half-life of uranium-238 is 4.463×1011 years longer. What is the half-life of uranium-238? The answer should be in decimal form.
To find the half-life of uranium-238, you need to add the additional years to the half-life of uranium-235.
The half-life of uranium-235 is given as 700,000,000 years, and the half-life of uranium-238 is 4.463×10^11 years longer.
Adding these two time periods together, you get:
700,000,000 + 4.463×10^11
To add these two numbers, they need to be in the same format. Convert 700,000,000 to scientific notation:
700,000,000 = 7×10^8
Now the equation becomes:
7×10^8 + 4.463×10^11
To add these two numbers, the exponents need to be the same. Convert 7×10^8 to the same exponent as 10^11:
7×10^8 = 0.7×10^9
Now the equation becomes:
0.7×10^9 + 4.463×10^11
Adding the coefficients, you get:
0.7 + 4.463 = 5.163
Therefore, the half-life of uranium-238 is:
5.163×10^11 years.
The half-life of uranium-235 is given as 700,000,000 years, and the half-life of uranium-238 is 4.463×10^11 years longer.
Adding these two time periods together, you get:
700,000,000 + 4.463×10^11
To add these two numbers, they need to be in the same format. Convert 700,000,000 to scientific notation:
700,000,000 = 7×10^8
Now the equation becomes:
7×10^8 + 4.463×10^11
To add these two numbers, the exponents need to be the same. Convert 7×10^8 to the same exponent as 10^11:
7×10^8 = 0.7×10^9
Now the equation becomes:
0.7×10^9 + 4.463×10^11
Adding the coefficients, you get:
0.7 + 4.463 = 5.163
Therefore, the half-life of uranium-238 is:
5.163×10^11 years.
A mobile phone holds 1.28×1011 bytes of storage. You can also pay more money to get an additional 384,000,000,000 bytes. How much storage would your phone have if you buy the additional bytes? The answer should be in scientific notation.
To find the total storage of the phone if you buy the additional bytes, you need to add the additional bytes to the initial storage.
The phone initially holds 1.28×10^11 bytes of storage, and you can buy an additional 384,000,000,000 bytes.
Adding these two storage amounts together, you get:
1.28×10^11 + 384,000,000,000
To add these two numbers, they need to be in the same format. Convert 384,000,000,000 to scientific notation:
384,000,000,000 = 3.84×10^11
Now the equation becomes:
1.28×10^11 + 3.84×10^11
The exponents are already the same, so you can add the coefficients:
1.28 + 3.84 = 5.12
Therefore, the phone would have:
5.12×10^11 bytes of storage if you buy the additional bytes.
The phone initially holds 1.28×10^11 bytes of storage, and you can buy an additional 384,000,000,000 bytes.
Adding these two storage amounts together, you get:
1.28×10^11 + 384,000,000,000
To add these two numbers, they need to be in the same format. Convert 384,000,000,000 to scientific notation:
384,000,000,000 = 3.84×10^11
Now the equation becomes:
1.28×10^11 + 3.84×10^11
The exponents are already the same, so you can add the coefficients:
1.28 + 3.84 = 5.12
Therefore, the phone would have:
5.12×10^11 bytes of storage if you buy the additional bytes.
1 answer