Asked by Ashley
In an experiment 2.750 g of magnesium is reacted with 2.571 g of oxygen gas according to the equation:
Mg + O2 ==> MgO.
What mass of the other reactant is in exess?
You need equal number of moles of each. Which has the excess?
moles Mg=2.750/molmassMg
moles O2=2.571/32
One will have more than needed.(30*1.50)D+ (70+35)I=25500(30*1.50)D+ (70+35)I=25500
Mg + O2 ==> MgO.
What mass of the other reactant is in exess?
You need equal number of moles of each. Which has the excess?
moles Mg=2.750/molmassMg
moles O2=2.571/32
One will have more than needed.(30*1.50)D+ (70+35)I=25500(30*1.50)D+ (70+35)I=25500
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