To find the rate of change in the squirrel's height above the ground, we can divide the change in height by the time it took to make that change.
The squirrel moved from a perch 100 feet above the ground to its stored acorns in a hole 45 feet from the ground. This is a change in height of 100 - 45 = 55 feet.
The squirrel took 5.25 seconds to make this change in height.
So, the rate of change in the squirrel's height above the ground is 55 feet / 5.25 seconds = 10.48 feet per second.
Therefore, the quotient describes the rate of change in the squirrel's height above the ground as approximately 10.48 feet per second.