Question

A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel moved from a perch 100 feet above the ground to get to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel’s height above the ground. Give your answer to the nearest hundredth.(1 point)
Responses

The quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.

The quotient that describes the rate of change in the squirrel’s height above the ground is 19.05 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 19.05 feet/second.

The quotient that describes the rate of change in the squirrel’s height above the ground is −10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is , negative 10.48, feet/second.

The quotient that describes the rate of change in the squirrel’s height above the ground is −19.05 feet/second.

Answer 1

∆h/∆t = (45-100)ft/5.25s = ____ ft/s

Answer 2

A is the correct answer