Question

Solve for n.

-19 = -8 + n

A. -27
B. -11
C. 0
D. 11
E. 27

Answer 1

The width of a rectangle is doubled and its length is tripled.



How many times larger is the area of the enlarged rectangle compared to the area of the original rectangle?

A. 6
B. 10
C. 12
D. 24

Answer 2

i think your kind of wrong

Answer 3

3x + 2 = 7x - 6

A. x = - 2/5
B. x= 4/5
C. x = 1
D. x=2

Answer 4

point g is located at -17 on the number line. Point H is located at 5 on the number line.
What is the distance between Point G and Point H on the number line? Enter the answer in the box.

Answer 5

To solve for n, we need to isolate the variable n on one side of the equation.

-19 = -8 + n

We can simplify -8 + n by rearranging the terms:

n - 8 = -19

Next, we can isolate n by adding 8 to both sides of the equation:

n - 8 + 8 = -19 + 8
n = -11

Therefore, the solution is n = -11.

The correct answer is B. -11.

Answer 6

Let's assume the original width of the rectangle is w and the original length is l.

The area of the original rectangle is given by: A1 = w * l.

After the width is doubled and the length is tripled, the new width of the enlarged rectangle is 2w and the new length is 3l.

The area of the enlarged rectangle is given by: A2 = (2w) * (3l) = 6wl.

To find out how many times larger the area of the enlarged rectangle is compared to the original rectangle, we can divide the area of the enlarged rectangle by the area of the original rectangle: A2 / A1.

Dividing the two equations, we get:

A2 / A1 = (6wl) / (wl)

Canceling out the "wl" terms, we get:

A2 / A1 = 6

Therefore, the area of the enlarged rectangle is 6 times larger than the area of the original rectangle.

The correct answer is A. 6.

Answer 7

Apologies for the confusion in my previous response. Let's re-evaluate the problem.

If the width of a rectangle is doubled and its length is tripled, the new width and length can be expressed as 2w and 3l, respectively.

The area of the original rectangle is given by A1 = w * l.

The area of the enlarged rectangle is given by A2 = (2w) * (3l) = 6wl.

To find out how many times larger the area of the enlarged rectangle is compared to the original rectangle, we can divide the area of the enlarged rectangle by the area of the original rectangle: A2 / A1.

Dividing the two equations, we get:

A2 / A1 = (6wl) / (wl)

Canceling out the "wl" terms, we get:

A2 / A1 = 6

Therefore, the area of the enlarged rectangle is 6 times larger than the area of the original rectangle.

The correct answer is A. 6.

Answer 8

To solve the equation, we will start by isolating the variable x on one side of the equation.

3x + 2 = 7x - 6

Let's start by getting all the x terms on one side by subtracting 7x from both sides:

3x - 7x + 2 = 7x - 7x - 6

-4x + 2 = -6

Next, we'll isolate the constant term by subtracting 2 from both sides:

-4x + 2 - 2 = -6 - 2

-4x = -8

Now, we can solve for x by dividing both sides by -4:

(-4x) / -4 = (-8) / -4

x = 2

Therefore, the solution is x = 2.

The correct answer is D. x = 2.

Answer 9

To find the distance between Point G and Point H on the number line, we can subtract the coordinate of Point G from the coordinate of Point H:

Distance = | (coordinate of Point H) - (coordinate of Point G) |

Distance = | 5 - (-17) |

Distance = | 5 + 17 |

Distance = | 22 |

The distance between Point G and Point H on the number line is 22.

Answer: 22