Question
An athletic apparel manufacturer randomly selects 200 high school varsity basketball players. A mean height of 6.18 feet is calculated with a margin of error of ±0.15 for a 99% confidence interval.
Answers
GPT 3.5
To calculate the 99% confidence interval for the mean height, we need to use the formula:
Confidence Interval = mean ± (critical value × standard error)
The critical value is taken from the z-table for a 99% confidence level, which is 2.576.
The standard error can be calculated using the formula:
Standard Error = standard deviation / sqrt(sample size)
Since the sample size is 200, let's assume the standard deviation is known to be 0.5 feet.
Plugging these values into the formula:
Standard Error = 0.5 / sqrt(200) ≈ 0.035355
Now we can calculate the confidence interval:
Confidence Interval = 6.18 ± (2.576 × 0.035355)
Confidence Interval = 6.18 ± 0.091
Therefore, the 99% confidence interval for the mean height of high school varsity basketball players is approximately 6.09 to 6.27 feet.
Confidence Interval = mean ± (critical value × standard error)
The critical value is taken from the z-table for a 99% confidence level, which is 2.576.
The standard error can be calculated using the formula:
Standard Error = standard deviation / sqrt(sample size)
Since the sample size is 200, let's assume the standard deviation is known to be 0.5 feet.
Plugging these values into the formula:
Standard Error = 0.5 / sqrt(200) ≈ 0.035355
Now we can calculate the confidence interval:
Confidence Interval = 6.18 ± (2.576 × 0.035355)
Confidence Interval = 6.18 ± 0.091
Therefore, the 99% confidence interval for the mean height of high school varsity basketball players is approximately 6.09 to 6.27 feet.
Suppose you survey 500 shoppers at the Mall of America. A parameter of this population is
Responses
Responses
GPT 3.5
Unfortunately, without knowing what the parameter it is that we are interested in (e.g., average age, proportion of shoppers who own a car, etc.), it is not possible to provide a specific calculation or an exact confidence interval. Can you please provide more details about the parameter of interest?