Question

The water level of a river is below normal levels. Its water level is at 1 1/2
meters below sea level. During the summer, the river drops another 2 1/3
meters below sea level. What is the water level at the end of summer? Remember, the elevation is below sea level. Account for this in your answer. (1 point)

Answer 1

wrong

Answer 2

To determine the water level at the end of summer, we need to add the additional drop of 2 1/3 meters to the initial level of 1 1/2 meters below sea level.

To add these two measurements, we need to find a common denominator for the fractions. The least common multiple of 2 and 3 is 6.

Converting 1 1/2 to an improper fraction: 1 1/2 = 3/2
Converting 2 1/3 to an improper fraction: 2 1/3 = 7/3

Now that we have the fractions with a common denominator, we can add them together:

3/2 + 7/3

To add these fractions, we need to find a common denominator, which in this case is 6:

(3/2) x (3/3) = 9/6
(7/3) x (2/2) = 14/6

Now we can add the fractions:

(9/6) + (14/6) = 23/6

So the water level at the end of summer is 23/6 meters below sea level.

However, to have a simpler representation, we can divide the numerator by the denominator:

23 ÷ 6 = 3 remainder 5

This means the water level at the end of summer is 3 5/6 meters below sea level.

Answer 3

Apologies for the mistake. Let's correct it:

The water level of the river is initially 1 1/2 meters below sea level.
The river drops another 2 1/3 meters below sea level during the summer.

To find the total drop in water level, we need to add the initial drop and the additional drop.

1 1/2 + 2 1/3

Let's convert these mixed numbers into improper fractions:

1 1/2 = (2/2 + 1/2) = 3/2
2 1/3 = (3/3 + 1/3) = 7/3

Now, we can add the fractions:

3/2 + 7/3

To add these fractions, we need to find a common denominator, which is 6:

(3/2) x (3/3) = 9/6
(7/3) x (2/2) = 14/6

Now we can add the fractions:

9/6 + 14/6 = 23/6

So the total drop in water level at the end of summer is 23/6 meters below sea level.

To simplify this fraction, we can divide the numerator by the denominator:

23 ÷ 6 = 3 remainder 5

This means the water level at the end of summer is 3 5/6 meters below sea level.