Find the point-slope equation of the line with slope -3 that passes through the point (2,-10).

Answer 1

The point-slope equation of a line is given by y - y₁ = m(x - x₁), where (x₁, y₁) is a point on the line and m is the slope.

Using the given slope m = -3 and the point (2, -10), we substitute these values into the point-slope equation to get:

y - (-10) = -3(x - 2)

Simplifying:

y + 10 = -3x + 6

Moving 10 to the other side:

y = -3x + 6 - 10

Simplifying further:

y = -3x - 4

Therefore, the point-slope equation of the line with slope -3 that passes through the point (2, -10) is y = -3x - 4.