Asked by Chopsticks
If you add 2g of NaCl to 23mL of water, what is the boiling point?
.
2 g/molar mass Salt = 58.4425 mole of salt
delta T = Kb*m
delta T = 0.512 x 0.23 = 0.113 or about 113 C.
I tried to model this problem like you did, but I don't know if I did it correctly.
.
2 g/molar mass Salt = 58.4425 mole of salt
delta T = Kb*m
delta T = 0.512 x 0.23 = 0.113 or about 113 C.
I tried to model this problem like you did, but I don't know if I did it correctly.
Answers
Answered by
Bob
delta T = Kim
delta T = the change in boiling (or freezing) point (in degrees Celsius)
K= boiling point elevation (or depression) constant for the solvent
i = number of ions into which the solute dissociates
m = molality (moles solute / kg solvent)
delta T = the change in boiling (or freezing) point (in degrees Celsius)
K= boiling point elevation (or depression) constant for the solvent
i = number of ions into which the solute dissociates
m = molality (moles solute / kg solvent)
Answered by
DrBob222
Yes, delta T = iKb*molality is correct.
In this case, sucrose doesn't ionize; therefore, i is 1.
In this case, sucrose doesn't ionize; therefore, i is 1.
Answered by
DrBob222
I suppose I should have said, "In the other problem, sucrose doesn't ionize and i = 1." In the problem with NaCl, i = 2.
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